f4i ignition

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Old 10-17-2008 | 06:14 PM
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f4i ignition

does any body know what resistance the resistor in the ignition is,,, and has any one replaced it before,,,, i know where to get them iv worked with them in my superduty before,,,, i just dont know what resistor it is
Old 10-17-2008 | 06:20 PM
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Re: f4i ignition

you lose the key and trying to hot wire it or something?
Old 10-17-2008 | 06:24 PM
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Re: f4i ignition

Originally Posted by Stuntin73
you lose the key and trying to hot wire it or something?
the key has nothing to do with the resistance in the wirering in the ignition,,,
Old 10-17-2008 | 06:32 PM
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May not be a resistor.

I think it's a diode that only lets current flow one way. Or something like that. I'm not sure. I tried to figure it out in the past because I kept forgetting my key and showing up at the lot without it. I wanted to be able hotwire it so I could still ride but never figured it out. If someone knows I hope they share. Thanks.
Old 10-17-2008 | 06:32 PM
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Re: f4i ignition

unhook the ignition from the triple tree and the black box under the ignition is the resistor order a new one hook it up and your done, its cheap and easy.
Old 10-17-2008 | 06:34 PM
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People Who May Know...

Also, people who have put a auto-start alarm on their bike may also know. They have to bypass the ignition some way. Maybe an alarm forum or something? It's a stretch - but maybe.
Old 10-17-2008 | 06:36 PM
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Re: f4i ignition

Originally Posted by Bones315
unhook the ignition from the triple tree and the black box under the ignition is the resistor order a new one hook it up and your done, its cheap and easy.
Old 10-17-2008 | 06:58 PM
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Re: f4i ignition

first off its not a resistor its a zener diode...2nd pm me and ill tell you what ohm resistor you can use to reduce the voltage that it needs 99cents at radioshack
Old 10-17-2008 | 07:42 PM
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Re: f4i ignition

Originally Posted by slipperone
first off its not a resistor its a zener diode...2nd pm me and ill tell you what ohm resistor you can use to reduce the voltage that it needs 99cents at radioshack
WOW that just blew my mind

A Zener diode is a type of diode that permits current in the forward direction like a normal diode, but also in the reverse direction if the voltage is larger than the breakdown voltage known as "Zener knee voltage" or "Zener voltage". The device was named after Clarence Zener, who discovered this electrical property.

A conventional solid-state diode will not allow significant current if it is reverse-biased below its reverse breakdown voltage. When the reverse bias breakdown voltage is exceeded, a conventional diode is subject to high current due to avalanche breakdown. Unless this current is limited by external circuitry, the diode will be permanently damaged. In case of large forward bias (current in the direction of the arrow), the diode exhibits a voltage drop due to its junction built-in voltage and internal resistance. The amount of the voltage drop depends on the semiconductor material and the doping concentrations.

A Zener diode exhibits almost the same properties, except the device is specially designed so as to have a greatly reduced breakdown voltage, the so-called Zener voltage. A Zener diode contains a heavily doped p-n junction allowing electrons to tunnel from the valence band of the p-type material to the conduction band of the n-type material. In the atomic model, this tunneling corresponds to the ionization of covalent bonds. A reverse-biased Zener diode will exhibit a controlled breakdown and allow the current to keep the voltage across the Zener diode at the Zener voltage. For example, a diode with a Zener breakdown voltage of 3.2 V will exhibit a voltage drop of 3.2 V if reverse bias voltage applied across it is more than its Zener voltage. However, the current is not unlimited, so the Zener diode is typically used to generate a reference voltage for an amplifier stage, or as a voltage stabilizer for low-current applications.

The breakdown voltage can be controlled quite accurately in the doping process. While tolerances within 0.05% are available, the most widely used tolerances are 5% and 10%.

Another mechanism that produces a similar effect is the avalanche effect as in the avalanche diode. The two types of diode are in fact constructed the same way and both effects are present in diodes of this type. In silicon diodes up to about 5.6 volts, the zener effect is the predominant effect and shows a marked negative temperature coefficient. Above 5.6 volts, the avalanche effect becomes predominant and exhibits a positive temperature coefficient.

In a 5.6 V diode, the two effects occur together and their temperature coefficients neatly cancel each other out, thus the 5.6 V diode is the component of choice in temperature-critical applications.

Modern manufacturing techniques have produced devices with voltages lower than 5.6 V with negligible temperature coefficients, but as higher voltage devices are encountered, the temperature coefficient rises dramatically. A 75 V diode has 10 times the coefficient of a 12 V diode.

All such diodes, regardless of breakdown voltage, are usually marketed under the umbrella term of "zener diode".

[edit] Uses

Zener diodes are widely used to regulate the voltage across a circuit. When connected in parallel with a variable voltage source so that it is reverse biased, a zener diode conducts when the voltage reaches the diode's reverse breakdown voltage. From that point it keeps the voltage at that value.

In the circuit shown, resistor R provides the voltage drop between UIN and UOUT. The value of R must satisfy two conditions:

1. R must be small enough that the current through D keeps D in reverse breakdown. The value of this current is given in the data sheet for D. For example, the common BZX79C5V6[1] device, a 5.6 V 0.5 W zener diode, has a recommended reverse current of 5 mA. If insufficient current exists through D, then UOUT will be unregulated, and less than the nominal breakdown voltage (this differs to voltage regulator tubes where the output voltage will be higher than nominal and could rise as high as UIN). When calculating R, allowance must be made for any current through the external load, not shown in this diagram, connected across UOUT.
2. R must be large enough that the current through D does not destroy the device. If the current through D is ID, its breakdown voltage VB and its maximum power dissipation PMAX, then IDVB < PMAX.

A Zener diode used in this way is known as a shunt voltage regulator (shunt, in this context, meaning connected in parallel, and voltage regulator being a class of circuit that produces a stable voltage across any load). In a sense, a portion of the current through the resistor is shunted through the Zener diode, and the rest is through the load. Thus the voltage that the load sees is controlled by causing some fraction of the current from the power source to bypass it—hence the name, by analogy with locomotive switching points.

These devices are also encountered, typically in series with a base-emitter junction, in transistor stages where selective choice of a device centered around the avalanche/zener point can be used to introduce compensating temperature co-efficient balancing of the transistor PN junction. An example of this kind of use would be a DC error amplifier used in a stabilized power supply circuit feedback loop system.

Note that because it is almost always the reverse breakdown property of the Zener diode which is useful, in circuit schematics the Zener diodes typically point in the opposite direction of traditional diodes - the arrows point in the opposite direction to the current.
Old 10-17-2008 | 07:42 PM
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Re: f4i ignition

Originally Posted by slipperone
first off its not a resistor its a zener diode...2nd pm me and ill tell you what ohm resistor you can use to reduce the voltage that it needs 99cents at radioshack
pm sent
Old 10-18-2008 | 08:58 PM
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Re: f4i ignition

i know the key hsa nothing to do with the resistor but isnt the resistor in the key switch? and if it is i am saying if you lost the key and need to start the bike another way you dont need to hot wire it with another resister all you have to do is take apart you ignition switch. its easy and doesnt take long and then you can start the bike with just the lock cylinder and that can be used as your key and then when your done you just pull out the cylinder
Old 10-18-2008 | 09:01 PM
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Re: f4i ignition

uh yea anyways threat closed..i solved his issue
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